source : yahoo.com
Determine the pOH of a 0.227 M C5H5N solution at 25’C. The Kb of C5H5N is 1.7 x 10^-9?
the concept/math of the first answer is okay (the abbreviated version of doing an ICE table) but their calculated answer is wrong.
First we need to find the concentration of OH- using this equation:
[OH-] = Kw / [H+]
[OH-] = 1.0 x 10^-14 / ( [(1.7 x 10^-9)(0.227)]^2 )
** [H+] comes from ICE table
[OH-] = 5.1 x 10^-10
To find the pOH, we use [OH-] that we just calculated in this equation:
pOH = -log[OH-]
pOH = -log[5.1 x 10^-10]
pOH = 9.29
SOLVED: Determine the pH of a 0.5 moles/liter solution of – Fixya – Posted on Sep 25, 2011. Helpful 0. Ph calculation. Number of moles [H+] in first solution =concentration of [H+] in mol/L times the number of liters. You calculate the pH with the relation pH=-log(c) where c is the value of concentration in mol/L. ex: c[H+]= 3.57×10^(-6) pH: (-) [LOG] 3.57 [2nd]…10 Using the pH square and the equations learned in class, fill in the blank spots in the chart below: pH 0.0725% 0.055 7. For a 0.0034 M solution of C5H5N (Kb = 1.7×10-9) calculate: a. pH B (aq) Acid-Base Interactions Strong-Strong 1. What is the pH when 50 mL of 0.1 M HCl is mixed with 50 mL…Textbook solution for Chemistry & Chemical Reactivity 9th Edition John C. Kotz Chapter 16.2 Problem 1RC. We have step-by-step solutions for your textbooks written by Bartleby experts! 16.2 – The pH of a diet soda is 432 at 25C.
Unit 8 Homework Answers | Ph | Acid – The pH of an aqueous solution can be determined and calculated by using the concentration of hydronium ion … The pH of an aqueous solution is based on the pH scale which typically ranges from 0 to 14 in water (although as discussed below this is not an a formal rule).0.25 M HCOOH solution is found to have a pH of 2.19. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers…Now recall that the pH of a basic solution is Determined using the equation pH= 14-pOH. The pH of this NaOH solution is 24-3.54 = 10.46. The pH is given as -log([hydronium]), so the pH is 9. This is a trivial homework problem that is easy to solve, so that bothers me even more that is was asked here.
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