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## For The Function F(X) = −2(X + 3)2 − 1, Identify The Vertex, Domain, And Range.

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## Question

For the function f(x) = –2(x + 3)2 − 1, identify the vertex, domain, and range. The vertex is (3, –1), the domain is all real numbers, and the range is y ≥ –1. The vertex is (3, –1), the domain is all real numbers, and the range is y ≤ –1. The vertex is (–3, –1), the domain is all real numbers, and the range is y ≤ –1. The vertex is (–3, –1), the domain is all real numbers, and the range is y ≥ –1.

## Answer

we havewe know thatthe equation of a vertical parabola in vertex form is equal towhere is the vertexIf ——> then the parabola open upward (vertex is a minimum)If ——> then the parabola open downward (vertex is a maximum)In this problemthe vertex is the point so ——> then the parabola open downward (vertex is a maximum)The domain is the interval——-> (-∞,∞)that means——> all real numbersThe range is the interval——–> (-∞, -1]that meansall real numbers less than or equal to thereforethe answer isa) the vertex is the point b) the domain is all real numbersc) the range is see the attached figure to better understand the problem

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How to Find Range of a Function – MathCracker.com – EXAMPLE 1. Find the range of the function \(\displaystyle f(x) = \frac{x+1}{x-3}\): ANSWER: We proceed using the algebraic way: Let \(y\) be a number and we will solve for \(x\) in the following equation: \(f(x) = y\). The value \(y\) is in the range if \(f(x) = y\) can be solved for \(x\). In this case we have:1. For the function f(x) = -2(x + 3)^2 − 1, identify the vertex, domain, and range. A) The vertex is (3, -1), the domain is all real numbers, and the range is y ≥ -1. B) The vertex is (3, -1), the domain is all real numbers, and the range is y ≤ -1.Graph of \(x^2\). The quadratic function graph can be easily derived from the graph of \(x^2.\). Graph of \(x^2\) is basically the graph of the parent function of quadratic functions.. A quadratic function is a polynomial and their degree 2 which can be written in the general form,

2 algebra questions? multiple choice! 10 points!? | Yahoo – 1.find a and b 2. find vertex 3.find x value 4. find y value 5. the x and y are the vertexd. Show that the vertex form f(x) = \(\frac{1}{2}\)(x – 2) 2 – 4 is equivalent to the function given in part (a). EXPLORATION 2 Parabolas and Symmetry Work with a partner. Repeat Exploration 1 for the function given by f(x) = -\(\frac{1}{3}\)x 2 + 2x + 3 = -\(\frac{1}{3}\)(x – 3),sup>2 + 6. Communicate Your Answer. Question 3.Free functions vertex calculator – find function's vertex step-by-step This website uses cookies to ensure you get the best experience. By using this website, you agree to our Cookie Policy.

Graph of quadratic function | Vertex of a quadratic function – Suppose we have to find the range of the function f(x)=x+2. We can find the range of a function by using the following steps: #1. First label the function as y=f(x) y=x+2 #2. Express x as a function of y. Here x=y-2 #3. Find all possible values of y for which f(y) is defined. See that x=y-2 is defined for all real values of y. #4.Get an easy, free answer to your question in Top Homework Answers. For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range. The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2. The vertex is (-1, 2), the domain is all real numbers, and the range is y ≥ 2.Suppose the function k is defined as k(x)=f(x−3). Determine the domain and range of k. Domain: Range: Algebra. 1. Graph the function and identify the domain and range. y=-5x^2 oo=infinite A) Domain: (-oo, oo) Range: [0, oo) B) Domain: (-oo, oo) Range: (-oo, 0] C) Domain: (-oo, oo) Range: (-oo, 0] D) Domain: (-oo, oo) Range: [0, oo) 2.