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Graph the function f(x) = 5(0.21)x.
I assume you are working with an exponential function
f(x) = 5 * 0.21^x
All functions y = a^x go through the point (0,1)
so, clearly, yours must go through (0,5)
Now, when x=1, y = 5*0.21 = 1.05
Having reviewed the topic in your text, or online, you should now be able to sketch the curve. Just to make things easy, all exponential functions look basically the same. Just draw a typical curve, then label the axes appropriately.
Sep 24, 2019
Graph f(x)=-0.5|x+3|-2 | Mathway – Graph f(x)=-0.5|x+3|-2. Find the absolute value vertex. In this case, the vertex for is . Tap for more steps… To find the coordinate of the vertex, set the inside of the absolute value equal to . In this case, . Subtract from both sides of the equation. Replace the variable with in the expression.Which is the graph of g(x) = (0.5)x + 3 – 4? Image A first one The graph shows that f(x) = 3x is translated horizontally and vertically to create the function g(x) = 3x – h + k.We know that (0.5, 4) is not on the graph of x^2 because when x = 0.5, f(x) = 0.25. Since our function is now f(bx), and we know that x = 0.5, then we need to multiply 0.5 by something so that (b * 0.5)^2 = 4. We can now solve for b (b * 0.5)^2 = 4. take the square root of both sides of the equal sign
Translations of Exponential Functions Flashcards | Quizlet – Graph f (x)=0.5 (4)^x f (x) = 0.5(4)x f (x) = 0.5 (4) x Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0 y = 0.Graph f(x)=5-x. Rewrite the function as an equation. Reorder and . Use the slope-intercept form to find the slope and y-intercept. Tap for more steps… The slope-intercept form is , where is the slope and is the y-intercept. Find the values of and using the form .Find the intercepts and asymptotes, plot a few points, and then sketch the graph. f(x)=4^x Step 1. Find the domain and range. f(x) is defined for all real values of x, so the domain is the set of all real numbers. 4^x>0, so the range is f(x)>0 Step 2. Find the y-intercept. Let x=0. y= 4^0 = 1 The y-intercept is at (0,1). Step 3. Find the x-intercept.
if the point (2,4) is on the graph of f(x)=x^2 what is the – Find f(x) for x = 0 f(x) = 0.5(4^x) f(0) = 0.5 * 4^0 f(0) = 0.5 * 1 = 0.5 The graph must contain point (0, 0.5). Now find f(1). f(x) = 0.5(4^x) f(1) = 0.5 * 4^11. Graph a function y=f(x) that satisfies all the following criteria: – xs lim f(x) = 0, lim f(x)=0, limf(x)=0 f(x)is continuous on (-0,5) and (5,00) f(-7)=-2, f(-4which of these could be the graph of f(x) = 3 (0.5)x? Answer Save. 2 Answers. Relevance. Niall. Lv 7. 6 years ago. Favorite Answer. B is a parabola (seen in quadratic equations), so it is definitely not B. An exponential less than one but greater than zero will increase for negative values and decrease for positives: