source : socratic.org

## What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of -30.0 nC?

The force between two charges is given by Coulomb’s Law:

#|F|=k(|q_1||q_2|)/r^2#

Where #k# is a constant equal to #8.99*10^9(N*m^2)/C^2#

We are given that #r=8.00cm=0.08m# and #q_1=q_2=-30.0nC=-30.0*10^-9C#

#=> |F|=(8.99*10^9(N*m^2)/C^2)((30.0*10^-9C)(30.0*10^-9C))/(0.08m)^2#

#~~1.26xx10^-3N#

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